43.1k views
0 votes
al lanzar 2 dados las sumas de sus caras superiores es 7. Hallar la probabilidad de que unas de las caras haya sido 3

2 Answers

4 votes

Answer:

Suceso A= (6;4) (5;5) (4;6)

n(A)= 3

Suceso B= (5;5)

n(B)= 1

P(AnB)= (5;5)= 1

Espacio muestral= 36

P(B/A)= 1/36 / 3/36= 0.33= 33%

Suceso C= (4;6) (6;4)

n(C)= 2

P(AnC)= (4;6) (6;4)

P(AnC)= 2

P(C/A)=2/36 / 3/36= 2/3= 0.66= 66%

User Cassy
by
8.2k points
2 votes

Answer:

15/216 (6.944%)

Tienes suerte, me tomé 5 años de español! Hoep me ayudó!


User Kevin Garay
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories