Question

what is the equation of the line that is perpendicular to 5x+6y=16 and passes through the point (-5,7)?

Answer 1

y=6/5x+13

Explanation:

6y=-5x+16

Divide by 6

y=-5/6x + 8/3

Slope: 6/5 (opposite reciprocal)

7=-5(6/5)+b

7=-6+b

b=13