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What are the excluded values of x for x^2-3x-28/x^2-2x-35

User Rosenda
by
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2 Answers

2 votes

Answer:

The excluded values of given expression are 5 and 7.

Explanation:

Given expression,


(x^2-3x-28)/(x^2-2x-35)

Excluded values are values that will make the denominator of a fraction equal to 0.

Here, the denominator =
x^2-2x-35

So, for excluded values,


x^2-2x-35=0


x^2-7x+5x-35=0 ( By middle term splitting )


x(x-7)+5(x-7)=0


(x+5)(x-7)=0

If x + 5 = 0 ⇒ x = -5,

Or If x - 7 = 0 ⇒ x = 7,

Thus, the excluded values of given expression are 5 and 7.

User The Bomb Squad
by
7.9k points
5 votes

Answer:

-5 and +7

Explanation:

f(x) = (x²- 3x - 28)/(x² - 2x - 35)

The excluded values of x are those that make the denominator equal to zero.

x² - 2x – 35 =0

(x – 7)(x + 5) =0

x - 7 = 0

x = 7

x+ 5 = 0

x = -5

The excluded values of x are -5 and +7.

User Suryasankar
by
8.4k points

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