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What is the equation of a line that passes through the point(2 "-10" and is parallel to 14x+2y=6

User Jedge
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1 Answer

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19 votes

Answer:

y = 4 − 7x

Explanation:

The equation of the line in the slope-intercept form is y = 3 − 7x.

The slope of the parallel line is the same: m = −7.

So, the equation of the parallel line is y = −7x + a.

To find a, we use the fact that the line should pass through the given point: −10 = (−7) x (2) + a.

Thus, a = 4.

Therefore, the equation of the line is y = 4 − 7x.

User Crawler
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