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How much heat is absorbed by a 56g iron skillet when its temperature rises from 7oC to 28oC?

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The heat absorbed is calculated with the help of the formula,

Q = mCΔT

Q is heat absorbed, m is mass given as 56 gms, C is the specific heat of iron, that is, 0.449 J/g°C, and delta T is the change in temperature, which is 28 - 7 = 21°C

Thus, Q = 56 × 0.449 × 21 = 528 J

User MBMJ
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