Question

How far must you stretch a spring with k = 1800 N/m to store 270 J of energy?

Express your answer in meters.

Answer 1

0.55m

Step-by-step explanation:

Given parameters:

Spring constant = 1800N/m

Elastic potential energy = 270J

Unknown:

extension = ?

Solution:

To solve this problem, we use the formula of the elastic potential energy;

E. P =
`(1)/(2)` k e²

E.P is the elastic potential energy

k is the spring constant

e is the extension

270 =
`(1)/(2)` x 1800 x e²

e = 0.55m