Question

A pro basketball player has a vertical leap of 3333 in. What is his hang​ time? (Use V=48T2​.)

Answer 1

Hang time of the basketball player is 0.83 sec.

Explanation:

A pro basketball player has a vertical leap of 33 in.

His hang-time can be calculated by the function given by,

`V=48t^2`

Where,

V = vertical leap (vertical leap is the act of raising itself in the vertical plane)

t = the time for which the object stays in the air

Putting all the values,

`\Rightarrow 33=48t^2`

`\Rightarrow t^2=(33)/(48)`

`\Rightarrow t=\sqrt{(33)/(48)}`

`\Rightarrow t=0.83\ sec`

Therefore, hang time of the basketball player is 0.83 sec.