Question

Factor 9abc+3ac+12bc completely

Answer 1

`3c(3(b+1)a+4b)`

Explanation:

The given equation is:

`9abc+3ac+12bc`

Taking 3c common from all the above terms, we get

⇒
`3c(3ab+a+4b)`

⇒
`3c(3(b+1)a+4b)`

which is the required factorised form.