Question

Can someone please help me??

Answer 1

You didn't specify which problems you needed and you are only allowed to submit three questions in one posting so I chose to solve 1, 3, and 5.

NOTES:

Inverse means to swap the x's and y's and solve for "y"

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1. Answer: y =
`(2x+4)/(3)`

Explanation:

y =
`(-4+3x)/(2)`

swap: x =
`(-4+3y)/(2)`

2x = -4 + 3y

2x + 4 = 3y

`(2x+4)/(3)` = y

3. Answer: y = -3(x - 1)

Explanation:

y =
`-(1)/(3)x` + 1

swap: x =
`-(1)/(3)y` + 1

x - 1 =
`-(1)/(3)y`

-3(x - 1) = y

5. Answer: y =
`-(4)/(9)`(x - 4)

Explanation:

y = 4 -
`(9)/(4)x`

swap: x = 4 -
`(9)/(4)y`

x - 4 =
`-(9)/(4)y`

`-(4)/(9)`(x - 4) = y