Question

Please answer quickly, more might be coming soon. 50 Points!

Answer 1

2) ∠SDH and ∠SDT are right angles because SD ⊥ HT.

3)
`\bar{SH}\cong \bar{ST}` as it is given in the question.

4)
`\bar{SD}\cong \bar{SD}` is the reflexive property.

5) ΔSHD ≅ ΔSTD by RHS congruency.

Explanation:

Given in the question:

`\bar{SH}\cong \bar{ST}\\\bar{SD}\perp \bar{HT}`

In ΔSHD and ΔSTD

`\bar{SH}\cong \bar{ST}` (Given)

`\angle SDH\cong \angle SDT=90^o` (SD ⊥ HT)

`\bar{SD}\cong \bar{SD}` (Common)

Therefore,
`\Delta SHD\cong \Delta STD` (By RHS rule)

Reflexive property of congruency is defined as the property in which something is equal to itself. Hence, the reflexive property of these two triangles is
`\bar{SD}\cong \bar{SD}`