Question

Draw the net force arrow on the picture.

Where does the arrow go?? up, down, side, angle, etc? ​

Answer 1

Vector points up in NE direction at an angle of 26.57° from the horizontal. The size of the vector is 22.36N

Step-by-step explanation:

This is a problem relating to two vectors and the addition of the two vectors to get the resultant force

The two vectors are 10N pointing North (+ve y-axis) and 20N pointing East (+ve x-axis

These are indicated by their (x, y) values

So we have (0, 10) pointing north and (20,0) pointing east

Use the head-to-tail method to graphically add the two vectors. The tail of the 10N vector arrow is placed at the head of the 20N vector arrow

Then draw an arrow from the tail of the first vector to the head of the second vector to get the resultant vector. The resultant vector is (20, 10)

See the graph

The magnitude of the resultant vector is given by the Pythagorean theorem

=
`√((20^2 + 10^2) \\\\= √(400 + 100) \\\\= √(500)\\\\=22.36068N\\\\The angle of the vector , $\theta$, relative to the x-axis is computed by the formula $\tan\theta = (A)/(B)$\\\\So, $\theta$ = tan^(-1)\left((10)/(20)\right) \\= tan^(-1)\left((1)/(2)\right) \\\\= 26.57^\circ$\\\\\\`