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Suppose logbx = logcx, where b ≠ c. Then the value of x can be

A) 0 only
B) 1 only
C) b^c or c^b only
D) any positive real number

1 Answer

5 votes

Not A: We can't have
x=0 because
\log0 is undefined for a logarithm of any base.

B is true:
\log1=0 for any base.

Not C: If
x=b^c, then
\log_bb^c=c, but
\log_cb^c=c\log_bc which only reduces to
c if
\log_bc=1. This can only happen if
b=c, however, but we've assumed otherwise.

Not D: The reasoning for C not being correct is enough to rule out this possibility.

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