Question

PLEASE HELP!! Sulfur dioxide gas and oxygen gas react to produce gaseous sulfur trioxide. What mass of sulfur trioxide is produced when 125 g of sulfur dioxide reacts with 50.00 g of

oxygen to produce sulfur trioxide as the only product.
2SO2(g) + O2(g) —> 2SO3(g)

Answer 1

Mass = 156.195 g

Step-by-step explanation:

Given data:

Mass of SO₂ = 125 g

Mass of O₂ = 50.00 g

Mass of SO₃ produced = ?

Solution:

2SO₂ + O₂ → 2SO₃

Number of moles of SO₂:

Number of moles = mass/molar mass

Number of moles = 125 g/ 64.1 g/mol

Number of moles = 1.95 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 50.00 g/ 32 g/mol

Number of moles = 1.56 mol

Now we will compare the moles of SO₃ with SO₂ and O₂

O₂ ; SO₃

1 ; 2

1.56 : 2/1×1.56 = 3.12 mol

SO₂ ; SO₃

2 ; 2

1.95 : 1.95

Less number of moles of SO₃ are produced by SO₂ it will act as limiting reactant:

Mass of SO₃ :

Mass = number of moles × molar mass

Mass = 1.95 mol × 80.1 g/mol

Mass = 156.195 g