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Frank invests $1,000 in simple interest investment account that pays 8% a year. After a number of years, he withdraws his balance of $2,200. Using the formula l=prt, how many years was his money invested? 2.75 years 10 years 15 years 27.5 years

User Sullivan
by
6.8k points

2 Answers

4 votes

Answer:

15

Explanation:

User Vrasidas
by
7.0k points
2 votes

Answer:


15\ years

Explanation:

we know that

The simple interest formula is equal to


I=P(rt)

where

A is the Final Investment Value

I is the amount of money in Interest

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have


t=?\ years\\ P=\$1,000\\ A=\$2,200\\r=0.08

Find the interest I


I=A-P=\$2,200-\$1,000=\$1,200

substitute in the formula above


\$1,200=\$1,000(0.08t)

Solve for t


t=1.2/0.08=15\ years

User Mohd Shibli
by
6.7k points
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