Question

Use slope-intercept form, y = mx + b, to find the value for the y-intercept (b) of a line that has a slope of 6 and passes through the point (3, –5).

b = (dropdown) –23, –14, 21, 33

What is the new equation written in slope-intercept form?
(dropdown) y = 6x – 23, y = 6x – 14, y = 6x + 21, y = 6x + 33

Answer 1

-23,
`y=6x-23`

Explanation:

We need slope intercept form but do not have the needed information. We will gather this information by using point slope form. The point-slope formula is
`y -y_(1) =m(x -x_(1))` where we substitute a point (x,y) for
`(x_(1),y_(1))`.

We have slope represented as m=6 and (3, -5). We input m and
`x_(1) =3\\y_(1)=-5`.

`y-(-5)=6(x-3)\\y+5=6(x-3)`

We now simplify the parenthesis and solve for y to have slope intercept form.

`y+5=6(x-3)\\y+5=6x-18\\y+5-5=6x-18-5\\y=6x-23`

The y-intercept is b of slope intercept form y=mx+b. Here b=-23.