Answer:
x = -11, -11/5, -1, -1/5, 1/5, 1, 11/5,11
Explanation:
The general formula for a third-degree polynomial is
f(x) = ax³ + bx² + cx + d
Your polynomial is
f(x) = 5x³ + 7x + 11
a = 5; d = 11
p/q = Factors of d/Factors of a
Factors of d = ±1, ±11
Factors of a = ±1, ±5
Potential roots are x = ±1/1, ±1/5, ±11/1, ±11/5
Putting them in order, we get the potential roots
x = -11, -11/5, -1, -1/5, 1/5, 1, 11/5, 11
(There are no rational roots. There is one irrational root and two imaginary roots.)