Question

A bridge foundation has a nominal load capacity of 1700kN. If the resistance factor for this foundation is 0.65, what is the ultimate factored load this foundation can carry using the LRFD method

Answer 1

The appropriate answer will be "2353.8 K". A further solution is given below.

Step-by-step explanation:

The given values are:

Ultimate capacity,

= 1700kN

Resistance factor,

F.S = 0.65

According to the the LRFD, the allowable bearing pressure will be:

⇒
`Pallo w = \phi_c* (Pn)/(F.S)`

On substituting the values, we get

⇒
`=0.9* (1700)/(0.65)`

⇒
`=2353.8 \ K`

According to the the ASD, the allowable bearing pressure will be:

⇒
`Pallow=(Pn)/(\Omega * F.S)`

On substituting the values, we get

⇒
`=(1700)/(1.67* 0.65)`

⇒
`= (1700)/(1.0855)`

⇒
`=1845.35 \ K`