2 Answers

Sinan Guclu · Answer 1 · 2019-10-27T14:39:40+0000

Answer:

t = 2 s

Step-by-step explanation:

As we know that when object comes back to its initial position then the displacement of the object will be zero

so here we can say by kinematics equation

$\Delta y = v_y t + (1)/(2)at^2$

here we know that

$\Delta y = 0$

v_y = 9.8 m/s

g = -9.8 m/s^2

now from above equation we know

$0 = 9.8 t - \frac{1]{2}9.8 t^2$

so from above equation we have

t = 2 s

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