Answer:
2
![(11)/(20)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ptq0s1gn2aeh5hosv6cdsidhqszlmfpzhv.png)
Explanation:
one way is to change the mixed numbers to improper fractions
5
=
and 2
=
![(27)/(10)](https://img.qammunity.org/2019/formulas/mathematics/college/7g6mb0kxn0877nrbr355mupko7xszj5p2z.png)
now we have
-
![(27)/(10)](https://img.qammunity.org/2019/formulas/mathematics/college/7g6mb0kxn0877nrbr355mupko7xszj5p2z.png)
We require the fractions to have a common denominator before we can subtract them.
the lowest common multiple of 4 and 10 is 20
multiply the numerator/denominator of the first fraction by 5 and the numerator/denominator of the second fraction by 2
=
-
![(27(2))/(10(2))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/oxtzrlko2bk77rc8zr21lf92hlxbt3ud0g.png)
=
-
![(54)/(20)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/r9onwzwvgvmpemleidcklybwl82791jbz1.png)
now subtract the numerators leaving the denominator
=
= 2
← in simplest form