Question

A galvanic cell has the overall reaction: zn(s) 2eu(no3)3(aq)  zn(no3)2(aq) 2eu(no3)2(aq) which is the half reaction occurring at the anode

Answer 1

Answer: The half reaction occurring at anode is
`Zn(s)\rightarrow Zn^(2+)(aq.)+2e^-`

Step-by-step explanation:

In a chemical cell, substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

`X\rightarrow X^(n+)+ne^-`

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

`X^(n+)+ne^-\rightarrow X`

For the given chemical cell reaction:

`Zn(s)+2Eu(NO_3)_3(aq.)\rightarrow Zn(NO_3)_2(aq.)+2Eu(NO_3)_2(aq.)`

Oxidation half reaction (anode):
`Zn(s)\rightarrow Zn^(2+)(aq.)+2e^-`

Reduction half reaction (cathode):
`Eu^(3+)(aq.)+e^-\rightarrow Eu^(2+)(aq.)` ( × 2 )

Here, zinc is loosing electrons and is getting oxidized and europium is gaining electrons and loosing electrons.

Hence, the half reaction occurring at anode is
`Zn(s)\rightarrow Zn^(2+)(aq.)+2e^-`

Answer 2

The half reaction that occur at the anode is

Zn (s)→ Zn²⁺ (aq) + 2e⁻

Explanation

• In galvanic cell oxidation take place at the the anode. That is there is lost of electrons at the anode.

• Zn loss two(2) electron to form Zn²⁺ ion.

• Zn is therefore oxidized since it's oxidation move from oxidation state 0 to oxidation state 2+.