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Jerome takes a math course and a science course for summer school. For every 5 hours Jerome spends studying math, he studies science for 4 hours. If Jerome spent a total of 54 hours studying last week, then how long did he study math?

User Sjstrutt
by
8.1k points

2 Answers

3 votes

Answer:


y= (54*4)/(9)=24

And then we can solve for x like this:


x = (5*24)/(4)=30

And the final solution would be 30 hours for math and 24 for the science course.

Explanation:

We need to define some notation first. Let

x= number of hours that he spent for the math course

y = number of hours that he spent for th science course

We have that the total of hours is 54, and we can write that like this:


x+ y = 54 (1)

And the other conditions is: " For every 5 hours Jerome spends studying math, he studies science for 4 hours" And we can write this like that:


(x)/(y)=(5)/(4)

And we can solve for x like this:


x = (5y)/(4)

And we can replace this into equation (1) and we got:


(5y)/(4) + y = 54

And if we do the algebra we got:


(9y)/(4) =54


y= (54*4)/(9)=24

And then we can solve for x like this:


x = (5*24)/(4)=30

And the final solution would be 30 hours for math and 24 for the science course.

User Marmarta
by
7.9k points
1 vote

Answer:

Jerome spent
30 hours studying mathematics

Explanation:

We were given that every 5 hours Jerome spends studying math. he studies science for 4 hours.

The ratio of Mathematics to Science is


5:4 respectively.

The total ratio is
5+4=9.


If Jerome spent a total of
54 hours studying last week, then the number of hours he spent studying mathematics is


=(5)/(9)* 54.



=(5)/(1)* 6.



=30 hours.



User Albertjan
by
7.6k points

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