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you slide across home plate during baseball game. If you have a mass of 82 kg, and the coefficient of kinetic friction between you and the ground is 0.45, what is the force of friction acting on you?

User Hoyhoy
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2 Answers

4 votes

Answer:

362 rounded, a p e x users

Step-by-step explanation:

User Masinger
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3 votes

m = mass of the person = 82 kg

g = acceleration due to gravity acting on the person = 9.8 m/s²

F = normal force by the surface on the person

f = kinetic frictional force acting on the person by the surface

μ = Coefficient of kinetic friction = 0.45

The normal force by the surface in upward direction balances the weight of the person in down direction , hence

F = mg eq-1

kinetic frictional force on the person acting is given as

f = μ F

using eq-1

f = μ mg

inserting the values

f = (0.45) (82) (9.8)

f = 361.6 N

User Chris Maggiulli
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8.6k points