Question

I have a hot air balloon that has 18.0 g helium gas inside of it. if the pressure is 2.00 atm and the temperature is 297k, what is the volume of my balloon?

Answer 1

Answer: 54.86 L

Step-by-step explanation:

Ideal gas equation:

PV = nRT

P: Pressure = 2.00 atm

V: Volume = ?

n: number of moles,

`n= \frac{\text {Given mass}}{\text{Molar mass}} = (18.0 g)/(4.0 g/mol) = 4.5 mol`

R: Gas constant = 0.0821 Latm/molK

T: Temperature = 297 K

`V = (4.5 mol * 0.0821 L atm/molK * 297 K)/(2.00 atm) = 54.86 L`