Question

I really need help with this since I have a math test tomorrow, I'd really appreciate it if someone could help.

How do I solve by finding a common base; (3/8)^2x=64/121

I don't know how to find common bases of certain exponential equations that have fractions in them.

Answer 1

Ok first of all, I EXTREMELY appreciate your use of parenthesis. Ok so first just raise both sides to the power of 1/2.


`((3)/(8))^(x)=(8)/(11)`

You'll see why I didn't include a negative. Then apply the log base 3/8 and you get


`x = log_{ (3)/(8) }( (8)/(11) )`
Then you split the log up and you get

`x = log_{ (3)/(8) }(8) - log_{ (3)/(8) }(11)`
You couldn't put a negative value for a log. That is why I excluded the negative part of the sqrt.