Question

The rectangle below has an area of 15x^3y^415x 3 y 4 square meters and a length of 3x^2y3x 2 y meters.What is the width of the rectangle?

Answer 1

The width of the rectangle is
`5xy^3`.

Explanation:

The area of a rectangle is the product of length and width of the rectangle.

`A=length* width`

It is given that the area of the rectangle is
`15x^3y^4` square meters and the length of the rectangle is
`3x^2y`.

`15x^3y^4=3x^2y* width`

`width=(15x^3y^4)/(3x^2y)`

`width=(3* 5* x^2* xy^3* y)/(3x^2y)`

Cancel out common factors 3x²y.

`width=5xy^3`

Therefore the width of the rectangle is
`5xy^3`.