Answer:
The required graph of the equation is shown below:
Explanation:
Consider the provided equation.
Solve the equation for x.
Now substitute x=1/3 in


So, the graph will be the lines which intersect at (1/3,10/3)
The correct graph is 3rd one.
Alternate method:
The equation
can be written as:

Draw the graph for both equation.
For

Substitute x=0 in above equation,


Substitute y=0 in above equation,



Now use the coordinate (0,2) and (-1/2,0) to draw the graph of straight line.
For

Substitute x=0 in above equation,

Substitute y=0 in above equation,


Now use the coordinate (0,3) and (-3,0) to draw the graph of straight line.
Hence, the required graph of the equation is shown below: