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Which two tables represent the same function?

x y
4 8
6 7
x y
4 5
6 4
x y
2 8
8 5
x y
2 10
6 14
x y
2 9
8 6

1 Answer

6 votes

Answer:

The 1st and the 5th tables represent the same function

Explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

(x2 , y2) is
(y-y_(1))/(x-x_(1))=(y_(2)-y_(1))/(x_(2)-x_(1))

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7


(y-8)/(x-4)=(7-8)/(6-4)


(y-8)/(x-4)=(-1)/(2)

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4


(y-5)/(x-4)=(4-5)/(6-4)


(y-5)/(x-4)=(-1)/(2)

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5


(y-8)/(x-2)=(5-8)/(8-2)


(y-8)/(x-2)=(-3)/(6)=====(y-8)/(x-2)=(-1)/(2)

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

∴ 2y - 16 = -x + 2 ⇒ add x and 16 for two sides

x + 2y = 18 ⇒ (3)

# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14


(y-10)/(x-2)=(14-10)/(6-2)


(y-10)/(x-2)=(4)/(4)======(y-10)/(x-2)=1

- By using cross multiplication

∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

∴ -8 = x - y ⇒ switch the two sides

x - y = -8 ⇒ (4)

# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

∵ x1 = 2 , x2 = 8 and y1 = 9 , y2 = 6


(y-9)/(x-2)=(6-9)/(8-2)


(y-9)/(x-2)=(-3)/(6)======(y-9)/(x-2)=(-1)/(2)

- By using cross multiplication

∴ 2(y - 9) = -1(x - 2) ⇒ simplify

∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

The 1st and the 5th tables represent the same function

User Gbabu
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