Answer:
-3 and 5
Explanation:
I would first start by picking a variable to cancel out (either the x or the y).
Let's suppose that you choose to eliminate the x value. Since you are adding the two equations, you need both coefficients of the x values to cancel out, having one be positive and one be negative.
The first equation would be multiplied by -3:
-3(2x - 5y = -21) = -6x + 15y = 63
The second equation would be multiplied by 2:
2(3x - 3y = -18) = 6x - 6y = -36
Therefore, if you do this to eliminate the y terms:
-3(2x - 5y = -21) = -6x + 15y = 63
5(3x - 3y = -18) = 15x - 15y = 90