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Find the missing numerators in each of the following fractions: a. 5⁄6 = ?⁄12 b. 2⁄4 = ?⁄36 c. 2⁄5 = ?⁄20 d. 4⁄25 = ?⁄100

User BcWeb
by
7.9k points

2 Answers

4 votes
A. 10
Multiply numerator and denominator by 2. So 6(2)=12 and 5(2)=10
B. 18
Multiply numerator and denominator by 9. So 4(9)=36 and 2(9)=18
C. 8
Multiply numerator and denominator by 4. So 5(4)=20 and 2(4)=8
D. 16
Multiply numerator and denominator by 4. So 25(4)=100 and 4(4)=16
User Simone Cabrino
by
7.7k points
3 votes

Answer:

To find: Missing Numerators.

let the missing variable in each part be x.

A).


(5)/(6)=(x)/(12)


(5)/(6)*12=x


x=10

Thus, Missing Numerator in this part is 10.

B).


(2)/(4)=(x)/(36)


(2)/(4)*36=x


x=18

Thus, Missing Numerator in this part is 18.

C).


(2)/(5)=(x)/(20)


(2)/(5)*20=x


x=8

Thus, Missing Numerator in this part is 8.

D).


(4)/(25)=(x)/(100)


(4)/(25)*100=x


x=16

Thus, Missing Numerator in this part is 16.

User Neits
by
8.5k points

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