Question

How many grams of carbon monoxide are needed to react with an excess of iron (III) oxide to produce 198.5 grams of iron? Fe2O3(s) + 3CO(g) --> 3CO2(g) + 2Fe(s)

Please SHOW WORK so I can understand the concept

Answer 1

The grams of carbon monoxide is 148. 68 g

calculation

Fe₂O₃(s) + 3CO (g) → 3 CO₂(g) + 2Fe (s)

Step 1: find the moles of CO

moles = mass÷ molar mass

from periodic table the molar mass of Fe =56 g/mol

moles = 198.5 g÷ 56 g/mol =3.54 moles

Step 2 : use the mole ratio to determine the moles of Co

from given equation Co: Fe is 3: 2

therefore the moles of CO = 3.54 moles x 3/2= 5.31 moles

Step 3 Find mass of Co

mass = moles × molar mass

from periodic table the molar mass of CO = 12+ 16 = 28 g/mol

= 5.31 moles × 28 g/mol = 148.68 g