Question

In the reaction: CH3COO-+NH4+----------CH3COOH+NH3 what is the reactant acid and its conjugate base?

Answer 1

In the given reaction, the reactant acid is NH4+ (ammonium ion) and its conjugate base is NH3 (ammonia).

Step-by-step explanation:

In the reaction CH3COO- + NH4+ → CH3COOH + NH3, the reactant acid is NH4+ (ammonium ion) and its conjugate base is NH3 (ammonia). The proton donor or acid in the reactants is NH4+ as it loses a proton to become its conjugate base, NH3. On the other side, CH3COO- (acetate ion) gains a proton in the reaction to form CH3COOH (acetic acid), so CH3COO- is the conjugate base and CH3COOH is its corresponding acid in the reaction.

When identifying acids and bases in such reactions, one should look for the species that donates a proton and the species that accepts a proton. The donor is the acid and after donating a proton it becomes the conjugate base. Similarly, the acceptor is initially a base and becomes the conjugate acid after accepting a proton.

Answer 2

Answer : The reactant acid and conjugate base in this reaction is,
`NH_4^` and
`NH_3`.

Explanation :

Conjugate acid : A species that is formed by receiving of a proton
`(H^+)` by a base is known as conjugate acid.

Conjugate base : A species that is formed by donating of a proton by an acid is known as conjugate base.

The given chemical reaction is,

`CH_3COO^-+NH_4^+\rightleftharpoons CH_3COOH+NH_3`

In this reaction,
`CH_3COO^-`(base) react with
`NH_4^`(acid) to give
`CH_3COOH`(conjugate acid) and
`NH_3`(conjugate base).

Therefore, the reactant acid and conjugate base in this reaction is,
`NH_4^` and
`NH_3`.