2 Answers

CYrixmorten · Answer 1 · 2019-03-24T13:38:42+0000

Answer: Option '2' is correct.

Explanation:

Since we have given that

A six-sided number cube is rolled.

Let A be the event of getting the first number rolled was 3 .

Let B be the event of getting 4.

Probability of getting the first number rolled was 3 is given by

P(A)=(6)/(36)=(1)/(6)

Probability of getting a 3 then a 4 is given by

$P(A\cap B)=(1)/(36)$

so, our required probability is given by

$P(B\mid A)=(P(A\cap B))/(P(A))=((1)/(36))/((1)/(6))=(1)/(6)$

Hence, Probability of getting a 3 and then a 4 given that the first number rolled was a 3 is
(1)/(6)

Therefore, Option '2' is correct.

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