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What is the equation of the line perpendicular to 2x-3y=13 that passes through the point (-6,5)
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What is the equation of the line perpendicular to 2x-3y=13 that passes through the point (-6,5)

User Stanislav Sinyagin
by
5.6k points

2 Answers

5 votes

Answer:

y=-1.5x-4

Explanation:

-3y=-2x+13

3y=2x-13

y=2/3x-13/3

Slope: -3/2

5=-6(-1.5)+b

5=9+b

b=-4

User Diego Mora Cespedes
by
4.6k points
1 vote

Answer:

the answer is y = (-3/2) - 4

Explanation:


User Jaugar Chang
by
4.9k points
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