Question

Physics student is dropped. If they reach the floor at a speed of 3.2 m/s, from what height did they fall?

Answer 1

0.52 m

Step-by-step explanation:

The motion of the studnet is an accelerated motion, with constant acceleration
`g=9.8 m/s^2` (acceleration of gravity) toward the ground. We can find the distance covered by the student (which is equal to the height from which he falls) by using the SUVAT equation:

`v^2 -u^2 = 2ad`

where

v = 3.2 m/s is the final speed

u = 0 is the initial speed

a = 9.8 m/s^2 is the acceleration

d is the distance covered

By re-arranging the equation, we find:

`d=(v^2-u^2)/(2a)=((3.2 m/s)^2-0)/(2(9.8 m/s^2))=0.52 m`