Question

Solve for the variable 2(3x+1)=3

Answer 1

Hello there!

Question:-

`\sf \longmapsto2(3x+1)=3`

We need to find the value of x.

Solution:-

`\sf \longmapsto2(3x+1)=3`

Distribute:-

`\sf \longmapsto \: (2)(3x)+(2)(1)=3`

On Simplification:-

`\sf \longmapsto \: 6x + 2 = 3`

Subtract 2 from both sides :-

`\sf \longmapsto 6x+2 - 2=3 - 2`

On Simplification:-

`\sf \longmapsto6x + 0 = 3 - 2`

`\sf \longmapsto6x = 1`

Divide the two sides by 6:-

`\sf \longmapsto \: (6x)/(6) = (1)/(6)`

Cancel 6/6, leave x, answer is 1x. 1/6 can't be cancelled.

`\sf \longmapsto \: ( \cancel6x)/( \cancel6) = (1)/(6)`

`\sf \longmapsto \: x = (1)/(6)`

In Decimal:-

`\sf \longmapsto \: x = 0.16`

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Henceforth,the value of x is :-

`\boxed{\huge\tt x = (1)/(6)}`

`\bold{OR,}`

`\boxed{\huge\tt x = 0.16}`

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Please let me know if you have any questions.

~MisterBrian

Answer 2

x = 1/6

Explanation:

2(3x+1)=3

Distribute.

6x + 2 = 3

Subtract 2 from both sides.

6x = 1

Divide by 6 on both sides.

x = 1/6