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The engine displacement of an automobile is the volume through which the piston moves from high to low position. If an engine has n cylinders, the displacement is D = pi(bore/2)^2 • stroke • n, where the bore is the diameter of the cylinder and stroke is the length of the piston's travel.

If bore = k/2 and stroke = h, simplify the expression, D, in terms of k and h for 8 cylinders.

If the bore is 4 inches, the stroke is 3.4 inches, and the engine has four cylinders, what is the displacement? Round your answer to the nearest tenth of a cubic inch.

User Gravian
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2 Answers

7 votes

Answer:


85.4 cubic inch

Explanation:

Given-

Displacement =
\pi ((bore)/(2) )^2 * stroke * n

Now,

bore is represented as
(k)/(2)

and stroke is represented as
h

and number of cylindres "n"
= 8

Substituting these values in above equation, we get -

Displacement
= \pi (((k)/(2) )/(2))^2*h*8\\= \pi (k^2)/(16) * h* 8\\= (\pi* k^2*h)/(2)

Now substituting the given values, in above equation we get -

Displacement
= (\pi* 4^2*3.4 )/(2)\\= (\3.14* 16*3.4 )/(2) \\ = 85.408\\= 85.41= 85.4cubic inch

User Sachin G S
by
7.9k points
2 votes

Answer:

  • D = (π/2)hk² . . . . for 8 cylinders
  • D = 170.9 in³

Explanation:

Substituting the given expressions for bore and stroke and 8 cylinders, you have ...

... D = π((k/2)/2)^2 · h · 8

... D = (π/2)hk^2 . . . . simplified expression for 8 cylinders

_____

For bore = 4 in, stroke = 3.4 in, n = 4, the displacement is ...

... D = π(4 in/2)^2 · (3.4 in) · 4 = 54.4π in^3

... D ≈ 170.9 in^3

User Emmylou
by
8.3k points