Question

How many grams of carbon monoxide are needed to react with an excess of iron (III) oxide to produce 198.5 grams of iron? Fe2O3(s) + 3CO(g) -----> 3CO2(g) + 2Fe(s) Show all work step by step please!

Answer 1

The grams of carbon monoxide that are needed to react is 148.68 grams

calculation

Step 1: find the moles of iron

moles =mass÷ molar mass

from periodic table the molar mass of Fe is 56 g/mol

= 198.5 g÷ 56 g/mol =3.54 moles

Step 2: use the mole ratio to determine the moles of carbon monoxide(Co)

that is from given equation Co : Fe is 3:2 therefore the moles of Co

= 3.54 x 3/2 = 5.31 moles

Step 3 : find mass of CO

mass = moles × molar mass

from periodic table the molar mass of Co = 12+16 = 28 g/mol

mass is therefore = 5.31 moles × 28 g/mol = 148.68 grams