Question

Number 26. Please answer

Answer 1

to get the slope of any straight line, we simply need two points off of it, let's use the ones from the picture.

`(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-4)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{(-4)}}} \implies \cfrac{3 +4}{4 +4}\implies {\LARGE \begin{array}{llll} \cfrac{7}{8} \end{array}}`

Answer 2

Slope: (7/8)

Explanation:

26.

(-4, -4), (4, 3)

(x₁, y₁) (x₂, y₂)

y₂ - y₁ 3 - (-4) 3 + 4 7

m = ----------- = ------------ = ----------- = --------

x₂ - x₁ 4 - (-4) 4 + 4 8

y - y₁ = m(x - x₁)

y - (-4) = (7/8)(x - (-4))

y + 4 = (7/8)(x + 4)

y + 4 = (7/8)x + (7/2)

-4 -4

-----------------------------

y = (7/8)x - (1/2)

I hope this helps!