Question

Find the indicated probability. In one town, 71% of adults have health insurance. What is the probability that 4 adults selected at random from the town all have health insurance

Answer 1

0.254

Explanation:

Given that:

Percentage of those having health insurance = 71%

p = 71 / 100 = 0.71

Number of adults selected at random, n = 4

Probability that 4 selected have health insurance :

p^n = 0.71^4 = 0.25411681

= 0.254