Question

How do u find the axis of symmetry for f(x) = 3(x+4)^2 + 1

Answer 1

x= -4 is the axis of symmetry

Explanation:

The parabola is written in the form y = a (x-h)^2 +k

The vertex is (h,k) and the axis of symmetry is at x=h.

Given f(x) = 3(x- -4)^2 + 1, the vertex is (-4,1) so the axis of symmetry is x= -4