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5th term in expansion of (x-2)^7
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5th term in expansion of (x-2)^7

User Vikas Mane
by
8.3k points

1 Answer

1 vote

Answer:

560x^3

Explanation:

The formula is

(r + 1)th term of (a + x)^n = nCr a^(n-r)x^r

So 5th term = (4 + 1)th term

= 7C4 x^(7-4) (-2)^4

= 35x^3*16

= 560x^3

User Akmalmzamri
by
8.0k points
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