Answer:
x=9 and x=1
Explanation:
If 6 is added to the square of an integer, the result is 3 less than 10 times that integer.
x^2 +6 = 10x-3
Subtract 10x from each side.
x^2 -10x +6 = 10x-10x-3
x^2 -10x +6 = -3
Now add 3 to each side.
x^2 -10x +6+3 = -3+3
x^2 -10x +9 = 0
Now we can factor the left side of the equation.
What numbers multiply together to give positive 9 and add together to give -10?
-9* -1 = 9 -9+-1 = -10
(x-9) * (x-1) = 0
Using the zero product property
x-9 = 0 and x-1 = 0
x-9+9 = 0+9 x-1+1 = 0+1
x=9 and x=1