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The answer is A. A circle is inscribed in a regular hexagon with side length 10 feet. What is the area of the shaded region?

Recall that in a 30 – 60 – 90 triangle, if the shortest leg measures x units, then the longer leg measures x√3 units and the hypotenuse measures 2x units.


(150√3 - 75π) ft^2

(300 – 75π) ft^2

(150√3 – 25π) ft^2

(300 – 25π) ft^2

The answer is A. A circle is inscribed in a regular hexagon with side length 10 feet-example-1
User Dan Fitch
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2 Answers

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Answer:

Option A. (150√3- 75π) ft².

Explanation:

In the given picture a circle is inscribed in a regular hexagon with a side length = 10 feet.

Formula of the area of a regular hexagon
=3(√(3) )/(2)(side)^(2)

=
=3(√(3) )/(2)(10^(2))

= 3√3×50 = 150×√3 feet²

Now we will calculate the area of circle inscribed.

Already given in the question that In a 30-60-90 triangle

Longer leg of triangle r = x√3 =
(10)/(2)√(3) = 5√3 feet

Now area of circle = π r² = π(5√3)² = 75π feet²

Area of shaded part = Area of Hexagon-Area of circle inscribed.

= (150√3 - 75π) ft²

User Delgan
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3 votes

Answer: its A

(150 – 75π) ft2



User King Of The Jungle
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