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On the main street, the tourists walked for s km with a speed of v km/hour. On the side road, the tourists walked twice the distance that they covered on the main street. How much time t (in hours) did the tourists spend if it is known that on the side road they walked with a speed that was 2 km/hour less than their speed on the main road? Find t when s=10, v=6.

2 Answers

2 votes

Answer:

6 hr 40 min

Explanation:

User JanR
by
5.9k points
7 votes

Answer:

6 2/3 hours

Explanation:

We assume the time of interest is the total time spent on the main road and side road.

In each case, ...

... time = distance/speed

On the main road, ...

... tmain = s/v

On the side road, ...

... tside = (2s)/(v -2)

Then the total time spent is ...

... ttotal = tmain + tside

... = s/v + (2s)/(v -2)

For s=10 and v=6, this is ...

... ttotal = 10/6 + 2ยท10/(6 -2) = 5/3 + 20/4 = 5/3 + 5 . . . . hours

... ttotal = 6 2/3 hours

On the main street, the tourists walked for s km with a speed of v km/hour. On the-example-1
User Jed Anderson
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6.2k points