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What is the answer for:

the sum of three consecutive odd numbers, the smaller of which is equal to 2n–1.

1 Answer

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Answer:
6n + 3

Explanation:

Since, Here the smaller number = 2n - 1

Since, Numbers are consecutive.

Therefore, remaining numbers are 2n - 1 + 2 , 2n - 1 + 2 + 2

= 2n +1, 2n +3

Thus, the sum of these all numbers = 2n - 1 + 2n + 1 + 2n +3

=
6 n +3 ( By equating the like terms)


User Mark Walet
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