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25 points
College Algebra

25 points College Algebra-example-1

1 Answer

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Let's solve this problem step-by-step.

Explanation:

The method which we will be using to solve this problem will be simultaneous equations.

Let's first write down the two equations as follows:

Equation No. 1 -

5x + y = - 5

Equation No. 2 -

- 15x - 3y = 9

PROBLEM SOLVING METHOD NO. 1 -

We will first make ( y ) the subject in the first equation and solve accordingly.

Equation No. 1 -

5x + y = - 5

y = - 5 - 5x

From this, we will substitute the value of ( y ) from the first equation into the second equation to solve for ( x ) accordingly.

Equation No. 2 -

- 15x - 3y = 9

- 15x - 3 ( - 5 - 5x ) = 9

- 15x + 15 + 15x = 9

- 15x + 15x = 9 - 5

0x = 4

PROBLEM SOLVING METHOD NO. 2 -

We will first make ( x ) the subject in the first equation and solve accordingly.

Equation No. 1 -

5x = - 5 - y

x = ( 5 - y ) / 5

From this, we will substitute the value of ( x ) from the first equation into the second equation to solve for ( y ) accordingly.

Equation No. 2 -

- 15x - 3y = 9

- 15 [ ( 5 - y ) / 5 ] - 3y = 9

[ ( - 75 + 15y ) / 5 ] - 3y = 9

- 15 + 3y - 3y = 9

3y - 3y = 9 + 15

0y = 24

FINAL ANSWER:

Both problem solving methods show that the problem doesn't have a unique solution. The system is inconsistent.

Hope this helps! :)
Have a lovely day! <3
User Houssam
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