the base of the pyramid is a square, meaning all of its sides are 24 inches.
the slant-height, or the altitude of the triangular face, is 20 inches.
now, we can simply get the area of the squarish base, and all four triangular faces, since each one has a base of 24 and a height of 20, sum them up, and that's the area of the pyramid.
![\bf \stackrel{\textit{area of the base}}{(24\cdot 24)}~~+~~\stackrel{\textit{area of the four triangles}}{4\left[\cfrac{1}{2}(24)(20) \right]}\implies 576~~+~~960\implies 1536](https://img.qammunity.org/2019/formulas/mathematics/middle-school/sbklxmn3rz4vmbxnc4u4dzmw8l8d9wf7m0.png)