Question

For f(x)=3x+1 and g(x)=(x^2)-6, find (g/f)(x).

Answer 1

Answer: x^2-6/3x+1,x not equal to -1/3

Explanation:

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Answer 2

`f(x)=3x+1;\ g(x)=x^2-6\\\\\left((g)/(f)\right)(x)=(g(x))/(f(x))\\\\\boxed{\left((g)/(f)\right)(x)=(x^2-6)/(3x+1)}`