Question

If f(x)=2x+1 and g(x)=(x^2)-7, find (f/g)(x).

Answer 1

`f(x)=2x+1;\ g(x)=x^2-7\\\\\left((f)/(g)\right)(x)=(f(x))/(g(x))\\\\\boxed{\left((f)/(g)\right)(x)=(2x+1)/(x^2-7)}`

Answer 2

Value of (f/g)(x) is:

`(2x+1)/(x^2-7)`

Explanation:

f(x)=2x+1 and g(x)=x²-7

`((f)/(g))(x)=(f(x))/(g(x))`

⇒
`((f)/(g))(x)=(2x+1)/(x^2-7)`

Hence, value of (f/g)(x) is:

`(2x+1)/(x^2-7)`