Question

The launching velocity of a missile is 20.0 m/s, and it is shot at 53° above the horizontal. What is the horizontal component of the velocity at launch?

Answer 1

Given that

velocity (v) = 20 m/s ,

angle of missile (Θ) = 53°

Determine, Horizontal component = v cos Θ

= 20 × cos 53

= 12 m/s